Assume that the ground temperature Tg is 40 F (10 C) and that the inside temperature of the basement is 68 F (20 C) for Problem 3. Estimate the temperature between the wall and insulation, T2 and between the gypsum board and insulation T1. Answer: T1 = 64.3 F; T2 = 49.36 F

Answers

Answer 1

At high temperatures, there is a large amount of radiative heat transfer via the fibre insulation employed in thermal protection systems (TPS) (1200 C).

At high temperatures, fibre insulation used in thermal protection systems (TPS) radiatively transfers a substantial amount of heat (1200 C). The TPS's ability to insulate can therefore be significantly affected by reducing the radiative heat transfer through the fibre insulation. Directly applying reflective coatings to the individual fibres of a fibrous insulation should reduce radiative heat transfer, resulting in a less effective thermally conductive insulation. Sol-gel processes have been used to create coatings with high infrared reflectivity. By using this method, fibre insulation can receive uniform coatings without noticeably increasing its weight or density. To assess coating performance, ellipsometry, scanning electron microscopy, and Fourier Transform infrared spectroscopy have all been used.

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Related Questions

What are the steps to configure your router in order?

Answers

Answer:

Explanation:Step 1: Decide where to place the router. ...

Step 2: Connect to the Internet. ...

Step 3: Configure the wireless router gateway. ...

Step 4: Connect gateway to router. ...

Step 5: Use app or web dashboard. ...

Step 6: Create a username and password. ...

Step 7: Update the router's firmware. ...

Step 8: Create a Wi-Fi password.

3. (10 pts) Let T be a MST of a given graph G. Will T still be the MST if we reduce the weight of exactly one of the edges in G by a constant c? Prove your answer Solution

Answers

Explanation suggests that the MST will not be the same as T when it converts to T.

What is a minimum spanning tree (MST)?

A minimum spanning tree (MST) for a weighted, connected and undirected graph is a spanning tree with weight less than or equal to the weight of every other spanning tree.

The new weight will be smaller than the original weight, or wnew < wnew, if we precisely lower the weight of one edge (let's say e).

There may now be two cases. - The modified edge e is a part of T and is a member of the MST. Since e is already a component of T, reducing its weight will also reduce the MST's weight. Consequently, the modified MST T is the same as the present MST T. (but with reduced weight by c).

The modified edge e does not belong to the MST since it is not a component of T. This might alter the existing MST since another MST that includes the updated edge e might exist with a lower weight. The MST does not change, thus if we find a situation where this is not the case, our assumption would be erroneous and T would not be the MST. This may be demonstrated by contradiction.

We may use the cyclic property of MST, which states that in order to obtain an MST, we need to eliminate the edge with the biggest weight in the cycle. The red edge in this graph was not included in the MST, hence its weight was reduced. The MST and the red edge combine to create a graph with a cycle. Using the cyclic property, subtract the cycle C's strongest edge to obtain the adjusted MST. O(V) time (where |V| is the number of vertices) can be used to complete this.

This suggests that the MST will not be the same as T when it converts to T.

Therefore, T will not surely be the MST if we reduce the weight of exactly one of the edges in G by a constant c as described by point 2.

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For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 412 MPa (59760 psi) is applied if the original length is 480 mm (18.90 in.)? Assume a value of 0.22 for the strain-hardening exponent, n.

Answers

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / [tex]0.02^{0.22[/tex]

K = 815.8165 Mpa

next, we determine the true strain

(εT) = (σT/ K)^1/n

given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

(εT) = 0.04481 mm

Now, we calculate the instantaneous length

[tex]l_i[/tex] = [tex]l_0e^{ET[/tex]

given that [tex]l_0[/tex] = 480 mm

we substitute

[tex]l_i[/tex] =[tex]480mm[/tex] × [tex]e^{0.04481[/tex]

[tex]l_i[/tex] =  501.998 mm

Now we find the elongation;

Elongation = [tex]l_i - l_0[/tex]

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

In a parking garage, each level is 18 feet apart, Each ramp to a level is 120 feet long. Find the measurement of elevation for each ramp?

Answers

Answer:

Sin(angle)=0.1538

Angle=arcsine(0.1538)

Angle is 8.85 degrees

Explanation:

Firstly draw a diagram showing a triangle with the required angle, a hypotenuse of 130 ft and an opposite side of 20 ft.

The sine of the angle required uses the formula Opposite/Hypotenuse

(i am not sure sure)

Only these people are allowed to attend Sprint Retrospective a. Scrum master and Development team b. Product owner and Development team c. Scrum master and Product owner d. Scrum Team

Answers

It is to be noted that only these people are allowed to attend Sprint Retrospective are: "Scrum master and Development team" (Option A)

What is the Sprint Retrospective?

The Sprint Retrospective is a meeting that takes place at the conclusion of each sprint in Scrum. It allows the Scrum team to reflect on the previous sprint and identify methods to enhance the process in the future.

It's aim is to identify what went well during the sprint, what may be improved, and how to achieve those improvements in the future. It is an essential component of the Scrum framework since it ensures that the team is always developing and changing to meet the demands of the project.

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Fill in the blank to output the quotient of dividing 100 by 42. print (100______42)​

Answers

Answer:

print(100/42)

Explanation:

This is the operand for division in python and some other languages.

Which of the following types of auditing requires access to source code? Question options: Use Case Testing Code Review In order for a subject to be _____, the system must first ____ the subject and then record the subject's actions. Question options: accountable, identify accountable, authorize A company needs to conduct testing of technical controls as part of an IT Security Audit. Which of the following types of testing allows the auditor to have full knowledge of the internals for the system(s) under test at the time the tests are being designed or selected? Question options: White box testing Gray box testing What is the primary difference between second party and third party audits? Question options: Second party audit teams are granted inside access to the organization's operations. Third party audit teams are limited in their access to the organization's operations. Second party audits are external audits conducted on behalf of a business partner. Third party audits are conducted to provide assurance of compliance with laws and regulations. Red Team testing has revealed weaknesses in how a company provisions and deprovisions user accounts. These weaknesses allowed the Red Team to exploit the username/login for a privileged account assigned to a system administrator who recently left the IT department for another position within the company. Which of the following is the most important business process to investigate to learn why the weaknesses exist so that they can be addressed using a policy-based solution? Question options: User Account Review Privileged identity management

Answers

The kind of auditing requires access to source code is Code Review. "In order for a subject to be accountable, the system must first authorize the subject and then record the subject's actions."The  types of testing allow the auditor to have full knowledge of the internals for the system(s) under test at the time the tests are being designed, or selected is White box testing.The difference, between the two, is that second party audit teams are granted inside access to the organization's operations. Third party audit teams are limited in their access to the organization's operations.The most important business process to investigate to learn why the weaknesses exist so that they can be addressed using a policy-based solution is User Account Review.

What is Code Review?

Code reviews, often known as peer reviews, serve to ensure the quality of the code base. Code reviews are rigorous analyses of code that are intended to detect flaws, improve code quality, and assist engineers in learning the source code.

To hold a subject accountable, the system must first approve the subject before recording the subject's behavior.

"White box testing" allows the auditor to have complete knowledge of the internals of the system(s) under test at the time the tests are devised or selected.

Because audit results may affect the customer's purchasing decisions, second-party audits are more formal than first-party audits. A third-party audit is carried out by an audit agency that is independent of the customer-supplier relationship.

User Account Review is the most critical business process to analyze in order to determine why the gaps exist and how they may be remedied utilizing a policy-based solution.

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Which of these is shown in the animation below?
A. Air spring
B. Coil spring
C. Shock absorber
D. Torsion bar

Answers

The answer is A. Air spring

A cylindrical rod of brass originally 10 mm in diameter is to be cold worked by drawing. The circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 380 MPa and a ductility of at least 15 %EL are desired. Furthermore, the final diameter must be 7.5 mm. Explain how this may be accomplished. Use the graphs given in previous question.

Answers

Answer:

Explanation:

From the information given:

original diameter [tex]d_o[/tex] = 10 mm

final diameter [tex]d_f =[/tex] 7.5 mm

Cold work tensile strength of brass = 380 MPa

Recall that;

[tex]\text {The percentage CW }= \dfrac{\pi (\dfrac{d_o}{2})^2 - \pi(\dfrac{d_f}{2})^2 }{\pi(\dfrac{d_o}{2})^2} \times 100[/tex]

[tex]\implies \dfrac{\pi (\dfrac{10}{2})^2 - \pi(\dfrac{7.5}{2})^2 }{\pi(\dfrac{10}{2})^2} \times 100[/tex]

[tex]\implies43.87\% \ CW[/tex]

→ At 43.87% CW, Brass has a tensile strength of around 550 MPa, which is greater than 380 MPa.

→ At 43.87% CW, the ductility is less than 5% EL, As a result, the conditions aren't met.

To achieve 15% EL, 28% CW is allowed at most

i.e

The lower bound cold work = 15%

The upper cold work = 28%

The average = [tex]\dfrac{15+28}{2}[/tex] = 21.5 CW

Now, after the first drawing, let the final diameter be [tex]d_o^'[/tex]; Then:

[tex]4.5\% \ CW = \dfrac{\pi (\dfrac{d_o^'}{2})^2 - (\dfrac{7.5}{2})^2}{\pi (\dfrac{d_o^'}{2})^2}\times 100[/tex]

By solving:

[tex]d_o^'} = 8.46 mm[/tex]

To meet all of the criteria raised by the question, we must first draw a wire with a diameter of 8.46 mm and then 21.5 percent CW on it.

Electronic rack-and-pinion systems use an electric motor to pump the hydraulic fluid through the hoses.

a. true
b. false

Answers

Electronic rack-and-pinion systems use an electric motor to pump the hydraulic fluid through the hoses. This statement is true.

The rack and pinion gearset is housed inside a metal tube, with each end of the rack protruding out and being attached to an axial rod. This is how it operates. When the steering wheel is twisted, the rack is moved by the pinion gear, which is mounted to the steering shaft. Based on the torque being given to the steering wheel by the driver, the steering wheel position, and the vehicle's speed, the EPS electronic control unit (ECU) determines the amount of aiding power required. With an applied force, the EPS motor rotates a steering gear, lowering the driver's necessary torque.

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How may the desire for a perfect lawn be related to environmental pollution? A. Lawns have little to do with environmental pollution. B. Perfect lawns require excess use of manual labor. C. Manicured lawns are subject to increased runoff. D. Lawns absorb pesticides and fertilizers and these chemicals leach out of the lawn and run into creeks, streams and eventually, rivers, with rain or watering, eventually reaching the ocean.

Answers

Answer:  is b

Explanation:

Suppose a student table has two columns, names and marks. How to get name and marks of top three students

Answers

Answer:

SELECT Name, Marks FROM Student s1 where 3 <= (SELECT COUNT(*) FROM Students s2 WHERE s1.marks = s2.marks)

Define hermetic compressor

Answers

Answer:

Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.

Fig_Q5
6. A steel rod is stressed by a tension force of 250 N. It is found that the rod has length of 45
m and diameter of 1.5 mm. If the modulus of elasticity of the steel rod is assumed as 2 x 105
MPa, determine the strain of the steel rod due to the applied force.

Answers

Answer:

The strain of the steel rod due to the applied force is 41.93

Explanation:

Modulus of elasticity is equal to stress divided by strain.

And stress is equal to force divided by area

Surface area of cylindrical rod

[tex]2\pi r (r+h)[/tex]

Substituting the given values we get -

[tex]2 *3.14 * \frac{1.5}{1000} * 45 (45 + \frac{1.5}{1000}) = 19.07[/tex]

[tex]2 * 10 ^5 = \frac{250}{19.07 * S=(\frac{\Delta L}{L} )}[/tex]

Hence, strain is equal to

Strain = 41.93

Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .

Answers

Answer: 50

Explanation:

The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with mean μ=1497 and standard deviation σ=322. A certain test-retake preparation course is designed for students whose SAT scores are in the lower 25%, percent of those who take the test in a given year. What is the maximum SAT score in 2014 that meets the course requirements?

Answers

Answer:

1279

Explanation:

We have the mean u = 1497

Standard deviation sd = 322

We find the x distribution using 25%

P(Z<z) = 0.25

Z = -0.675

From here we use the formula for z score

X = z(sd) + u

X = -0.675*322 + 1497

X = -217.35 + 1497

X = 1279.6

Which is approximately 1279

So we conclude that the maximum sat scores in year 2014that meets with the requirements of this course is 1279

Answer:

1831

Explanation:

which of the following code segments will move the robot from the center square along the same path as the code segment above?

Answers

count ← 0

REPEAT 4 TIMES

{

count count + 1

REPEAT count TIMES

{

MOVE_FOWARD ()

}

ROTATE_LEFT ()

}

Which of the following best describes the typical method by which messages are transmitted over the Internet?

The message is broken into bundles that are communicated in a predefined request. Every bundle should be gotten in the request it was sent for the message to be accurately reassembled by the beneficiary's gadget.

Which of the following best shows how keylogging can be used to get into a computer system without permission?

A user installs a program on their computer that records and transmits all user input unintentionally.

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Identify parts of the E-Cig that constitute voltage, current, and resistance. Discuss the role each plays in the E-Cig and typical values for each including units.
Discuss the electrical dangers of an E-Cig. Give specific examples.
There are many electrical safety rules. Pick one, and discuss its application on a small system, such as the E-Cig.

Answers

Answer: c

Explanation:

state the parallelogram law of forces​

Answers

Answer:

The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram drawn from .

The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude

Which of these parts reduces the amount of pollutants in the engine exhaust?
A. Transmission
B. Catalytic converter
C. Tailpipe
D. Muffler

Answers

Answer:

Option B

Explanation:

Catalytic convertor with in the exhaust pipes of any vehicle converts harmful gases (such as hydrocarbons (HC), carbon monoxide (CO) and nitrogen oxides (NOx)) produced by combustion of fossil fuels (petrol, diesel etc.) into less harmful/toxic pollutants by acting as a catalyst for redox reaction. A catalytic convertor releases some mild gases from the exhaust like less harmful CO2, nitrogen and water vapour (steam)

Hence, option B is correct

can someone please help me with this
I've an exams tomorrow ​

Answers

Answer:

I am in Eight Grade

Explanation:

Barries of effective
communication?

Answers

Answer: barries

Explanation:

Three spheres are subjected to a hydraulic stress. The pressure on spheres 1 and 2 is the same, and they are made of the same material. The fractional compression on the third sphere is equal to the fractional compression on the first sphere times the reciprocal of the fractional compression on the second. If the pressure on the third sphere is 150000 N/m2 , what is the Bulk Modulus for the third sphere

Answers

Answer:

"150000 N/m²" is the right approach.

Explanation:

According to the question, the pressure on the two spheres 1 and 2 is same.

Sphere 1 and 2:

Then,

⇒  [tex]P_1=P_2[/tex]

⇒  [tex]\frac{\Delta V_1}{V_1}=\frac{\Delta V_2}{V_2}[/tex]

and the bulk modulus be,

⇒  [tex]B_1=B_2[/tex]

Sphere 3:

⇒  [tex]\frac{\Delta V_3}{V_3} =\frac{\frac{\Delta V_1}{V_1} }{\frac{\Delta V_2}{V_2} } =1[/tex]

then,

⇒  [tex]P_3=B\times \frac{\Delta V_3}{V_3}[/tex]

⇒       [tex]=B\times 1[/tex]

⇒       [tex]=150000\times 1[/tex]

⇒       [tex]=150000 \ N/m^2[/tex]

Structural engineers use wireless sensor networks to monitor the condition of dams and bridges.

a. True
b. False

Answers

Answer: True

Explanation:

Structural engineering is simply referred to as a branch of civil engineering, and they help in the designing of structures like buildings, dams, tunnels, bridges, tunnels, etc. Structural engineers typically work as consultants.

Wireless sensor networks are used by structural engineers to monitor the condition of dams and bridges. Wireless sensor network refers are dedicated sensors that are used in monitoring the physical conditions of the bridges and to know if they're still in good conditions.

Explain what the engineering team should advise in the following scenario.

Situation: An engineering team is analyzing a problem with a dam near a large metropolitan area. The dam reservoir has a capacity of 300 billion cubic feet, and it produces hydroelectric power for local municipalities. The dam has developed a severe crack.

Answers

Answer: its c

Explanation:

Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a velocity of 5 m/s. At the exit, the refrigerant is a saturated vapor at -16oC. The evaporator flow channel has constant diameter of 1.7 cm. Determine the mass flow rate of the refrigerant, in kg/s, and the velocity at the exit, in m/s.

Answers

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature [tex]T_1 = -16^0\ C[/tex]

Quality [tex]x_1 = 0.2[/tex]

Outlet:

Temperature [tex]T_2 = -16^0 C[/tex]

Quality  [tex]x_2 = 1[/tex]

The following data were obtained at saturation properties of R134a at the temperature of -16° C

[tex]v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg[/tex]

[tex]v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg[/tex]

[tex]m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}[/tex]

[tex]\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}[/tex]

g Design of a spindle present in an existing design needs to be reviewed for use under new loading needs. It is currently designed to withstand combined torsional and compressive loading. The design team needs to determine what the maximum torque it can withstand before failing if a compressive, axial load of 15 kips is present. The ultimate compressive and tensile strengths of the material are 135 ksi and 40 ksi, respectively. Determine the torsional shear stress that will just cause failure using a non-conservative failure theory.

Answers

Answer: its c

Explanation:

In the production of soybean oil, dried and flaked soybeans are brought in contact with a solvent (often hexane) that extracts the oil and leaves behind the residual solids and a small amount of oil.

a. Draw flow diagram of the process, labeling the two feed streams (beans and solvent) and the leaving streams (solids and extract).
b. The soybeans contain 18.5 wt% oil and the remainder insoluble solids, and the hexane is fed at a rate corresponding to 2.0 kg hexane per kg beans. The residual solids leaving the extraction unit contain 35.0 wt% hexane, all of the non-oil solids that entered with beans, and 1.0% of the oil that entered the beans. For a feed rate of 1000 kg/h of dried flaked soybeans, calculate mass flow rates of extract and residual solids and the composition of extract.

Answers

Answer: its c

Explanation:

To read signs you need good focal vision

Answers

Answer:eyesight

Explanation:

Answer: This is true

Which of the following situations best describes the chemical weathering process of sedimentary rock?
answer choices
Sedimentary sandstone is carried away by water along the bedrock of a stream.
Sedimentary sandstone allows water to freeze and thaw inside its cracks.
Sedimentary limestone cliffs are battered by strong ocean waves.
Sedimentary limestone is exposed to acid rain at the top of a mountain.

Answers

A situation which best describes the chemical weathering process of sedimentary rock include the following: D. Sedimentary limestone is exposed to acid rain at the top of a mountain.

What is weathering?

In Geology, weathering can be defined as a biogeochemical process that involves both the physical and chemical breakdown of rock into smaller pieces or fragments called sediments.

Additionally, weathering is broadly classified into two (2) categories and these include the following;

Physical weatheringChemical weathering

During the chemical weathering process of sedimentary rock, sedimentary limestone that are found at the top of a mountain become exposed to acid rain.

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